United States presidential election in Arkansas, 1996

United States presidential election in Arkansas, 1996

1992 ←
November 5, 1996
→ 2000

 
Nominee Bill Clinton Bob Dole Ross Perot
Party Democratic Republican Reform
Home state Arkansas Kansas Texas
Running mate Al Gore Jack Kemp Pat Choate
Electoral vote 6 0 0
Popular vote 475,171 325,416 69,884
Percentage 53.74% 36.80% 7.90%

President before election

Bill Clinton
Democratic

Elected President

Bill Clinton
Democratic

The 1996 United States presidential election in Arkansas took place on November 5, 1996, as part of the 1996 United States presidential election. Voters chose 6 electors to the Electoral College, who voted for President and Vice President.

Arkansas was won by President Bill Clinton (D-AR) by a 17 percentage point margin of victory.[1] The presidential election in the Natural State was a critical victory for the Democratic ticket, because Arkansas is Clinton's home state. Dole did not put up a challenge in Arkansas, and neither did billionaire businessman Ross Perot (Ref-TX), who had unsuccessfully run for President as an Independent in the previous election. Perot in 1996 won 7.9 percent of the popular vote in the Natural State, a significant total for a third party candidate. As of 2011, the 1996 election was the last time that a Democratic Presidential nominee has won in Arkansas; the state has gone Republican in each presidential election, starting in 2000.

Results

United States presidential election in Arkansas, 1996
Party Candidate Votes Percentage Electoral votes
Democratic Bill Clinton (incumbent) 475,171 53.74% 6
Republican Bob Dole 325,416 36.80% 0
Reform Ross Perot 69,884 7.90% 0
Green Ralph Nader 3,649 0.41% 0
Libertarian Harry Browne 3,076 0.35% 0

References